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0.013x^2-1.18x+26.24=0
a = 0.013; b = -1.18; c = +26.24;
Δ = b2-4ac
Δ = -1.182-4·0.013·26.24
Δ = 0.02792
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.18)-\sqrt{0.02792}}{2*0.013}=\frac{1.18-\sqrt{0.02792}}{0.026} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.18)+\sqrt{0.02792}}{2*0.013}=\frac{1.18+\sqrt{0.02792}}{0.026} $
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